(5m^2)+8=303

Solution for (5m^2)+8=303 equation:

(5m^2)+8=303

We move all terms to the left:

(5m^2)+8-(303)=0

We add all the numbers together, and all the variables

5m^2-295=0

a = 5; b = 0; c = -295;
Δ = b2-4ac
Δ = 02-4·5·(-295)
Δ = 5900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5900}=\sqrt{100*59}=\sqrt{100}*\sqrt{59}=10\sqrt{59}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{59}}{2*5}=\frac{0-10\sqrt{59}}{10}
=-\frac{10\sqrt{59}}{10}
=-\sqrt{59}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{59}}{2*5}=\frac{0+10\sqrt{59}}{10}
=\frac{10\sqrt{59}}{10}
=\sqrt{59}
$